Sender.LocalAddr = 0.0.0.0 in DataReceived event

[HelgeLange]

Hi Danijel,
before I try some other components to determine the local ip adress, i'd like to ask, what would be the rtc way to do it..

I build a small upd example for myself to see, if I can improve the existing code of a service I'm running in my client installations.
It's just UdpClient/Server and it works fine. But when I try to return the ip adress the server is running on, the LocalAddr function returns 0.0.0.0

Code:

procedure TForm5.RtcUdpServer1DataReceived(Sender: TRtcConnection);
var S: String;
begin
  S := Sender.Read;
  If S = 'huhu' Then
    Sender.Write(Sender.LocalAddr);
  CodeSite.Send( csmLevel4, 'Data', S);
end;

the server config is :

Code:

  object RtcUdpServer1: TRtcUdpServer
    MultiThreaded = True
    ServerPort = '10103'
    OnClientConnect = RtcUdpServer1ClientConnect
    OnDataReceived = RtcUdpServer1DataReceived
    Left = 152
    Top = 120
  end

Any ideas ?
Thanks in advance,
Helge

[D.Tkalcec (RTC)]

LocalAddr of the Server is irrelevant for the Client. What does matter is the PeerAddr you get on the Client after receiving data from the Server.

Best Regards,
Danijel Tkalcec

[HelgeLange]

So i mounted the horse from the wrong side
Thanks for the quick reply!

Helge